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In the 8421 BCD code the decimal number 125 is written as???

Answer Posted / sunny

128 64 32 16 8 4 2 1
0 1 1 1 1 1 0 1

64+32+16+8+4+1=125

Dividing 125
by 2 we will get 1 or 0 as a remainder so for this problem
answer is 1111101=125 as mention above

Is This Answer Correct ?    18 Yes 22 No



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