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In the 8421 BCD code the decimal number 125 is written as???
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Answer Posted / sunny
128 64 32 16 8 4 2 1
0 1 1 1 1 1 0 1
64+32+16+8+4+1=125
Dividing 125
by 2 we will get 1 or 0 as a remainder so for this problem
answer is 1111101=125 as mention above
| Is This Answer Correct ? | 18 Yes | 22 No |
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