what does the following code do?
fn(int n,int p,int r)
{
static int a=p;
switch(n){
case 4:a+=a*r;
case 3:a+=a*r;
case 2:a+=a*r;
case 1:a+=a*r;
}
}
a.computes simple interest for one year
b.computes amount on compound interest for 1 to 4 years
c.computes simple interest for four year
d.computes compound interst for 1 year
Answer Posted / nila
d.computes compound interest for 1 year
| Is This Answer Correct ? | 0 Yes | 1 No |
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You have given 2 array. You need to find whether they will
create the same BST or not.
For example:
Array1:10 5 20 15 30
Array2:10 20 15 30 5
Result: True
Array1:10 5 20 15 30
Array2:10 15 20 30 5
Result: False
One Approach is Pretty Clear by creating BST O(nlogn) then
checking two tree for identical O(N) overall O(nlogn) ..we
need there exist O(N) Time & O(1) Space also without extra
space .Algorithm ??
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Posted 3 months ago #
#define true 1
#define false 0
int check(int a1[],int a2[],int n1,int n2)
{
int i;
//n1 size of array a1[] and n2 size of a2[]
if(n1!=n2) return false;
//n1 and n2 must be same
for(i=0;i
find the output? void r(int a[],int c, int n) { if(c>n) { a[c]=a[c]+c; r(a,++c,n); r(a,++c,n); } } int main() { int i,a[5]={0}; r(a,0,5); for(i=0;i<5;i++) printf("\n %d",a[i]); getch(); }
Add Two Numbers Without Using the Addition Operator