Answer Posted / jayesh pillai

square of kva= square of kw + square of kvar

here, a power system possess apparent power i.e. kva
it is divided into two components i.e kw active power and
kvar reactive power

kw = kva*(cos phi) and kvar = kva (sin phi)
here actual power i.e. responsible as a loss component and
thus losses occurs in line due to active power

reactive power does not does any useful work but it is
responsible for building up magnetic field in motors or any
inductive equipments

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