Answer Posted / venu

use XOR association operation.
I mean: a = b^a^b = a^b^b = a;[bec a^a =0 always]

int main()
{
int a[3] = {3,4,5};
int b[4] = {7,4,5,3};
int r,i;
int n=4;

r1 = b[3];

for(i=0;i<n-1;i++)
{
r1 = r1^a[i]^b[i];
}

printf("number = %d \n",r);
}

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