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What will be the output of the program?
public class Test {
public static void main(String args[]) {
ArrayList<String> list = new ArrayList<String>();
list.add("2");
list.add("3");
list.add("4");
list.add("5");
System.out.println("size :"+list.size());
for(int i=0;i<list.size();i++) {
list.remove(i);
}
System.out.println("size after:"+list.size());
}
}
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Answer Posted / sreekanth madamanchi
Step 1: The array size: 4
array is list[0]=2, list[1]=3, list[2]=4, list[3]=5;
i=0;i<4;i++
it removes the 0th element, means it removes 2.
now the array is list[0]=3, list[1]=4, list[2]=5
Step 2: Now the size of the array is 3
now i=1 (bcz i++)
i<3;i++
it removes the 1st element, means it removes 4 (Bcz i=1).
now the array is list[0]=3, list[1]=5
Step 3: Now the size of the array is 2
now i=2
the condition is fail in for loop (bcz i=2. means 2<2)
So it won't go inside the loop
So the size after:2
The final Output is
size :4
Size after:2
| Is This Answer Correct ? | 13 Yes | 0 No |
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