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Answer Posted / stylish_312
volatile int i=10;
main()
{
fun()
{
while(i==10)
{
...
}
printf("This will print..\n");
}
}
ANS:
if we are not using volatile int ,the loop will be keep on
exeecuting,so printf statement will not print...to break
this loop declare the variable as a volatile....
| Is This Answer Correct ? | 8 Yes | 2 No |
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