for mod-6(mod-N) counter 3(n) ff are required... i.e 2^n-1<N<=2^n

mod 6 counter : no. of FF used.

Question Posted / shobha rani

Answer Posted / shobha rani

for mod-6(mod-N) counter 3(n) ff are required...
i.e
2^n-1<N<=2^n
4<6<=8
that's why 3 FF are used.

Is This Answer Correct ?

5 Yes

0 No

Please Help Members By Posting Answers For Below Questions

how to answer for the question what is your strength and weakness?

2199

What is meant by optimization and what are different ways of optimiztion?

4147

Power bjt is a current controlled device. Why?

1165

Explain design 8421 to 2421 binary code converter?

1006

Why are using 4ma to 20ma for signal transfer. Why not 0 to 20ma?

976

What is the advantage of scr?

1084

Explain what are the two mechanisms of breakdown in a p-n junction?

1214

working and uses of current transformer?

2097

Define what is meant by operating point?

980

What is meant by small signal amplifier?

1146

Why does all cellular networks have same shape of sim? Why is it designed in such a particular shape? Does it have any other shape?

971

documentation on improved trace buffer via Selective Data Capture Using 2-D Compaction for Post-Silicon Debug

1996

Explain how to convert a jk flip flop into sr flip flop and vice versa, a sr flip flop into d or t flip flop and vice versa?

1117

What does the voltmeter in ac mode show?

986

In the OTA, the transconductance is controlled by A The ac supply voltage B A bias current C The input signal voltage D The manufacturing process

2037