Answer Posted / yogesh

as i-j=8 is connected that means
a) 1,9,17,25....are connected
b) 2,10,18.26... are connected
.
.
e) 5,13,19,27.. are connected
.
.

h) 8,16,24,32 .. are connected

|i-j| = 12 are connected
that means
t)1,13,25,27 are conncted
y)2,14,26,38 are connected
u)3,15,27,
i)4,16,28...

obv because of t, even a and e are connected.
so only four series left i.e. a,b,c,d
a and b can never be connected because of odd numbers can
never be connected to even numbers in both the series.
so only possibity left is whether a and u or b and i can
be connected .
lets see a and u
a start with 1 and increments by 8
u starts with 3 and inctements by 12
this can match somewhere only if
for any value of m and n following is true
3+12*m = 1+8*n => 1+6*m = 4*n which can never be true

hence maximum number of connecte elements is 4.

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