As t = 3,it goes to case 3.But there is no break in that case so it proce

f1()
{
f(3);}
f(int t)
{
switch(t);
{
case 2: c=3;
case 3: c=4;
case 4: c=5;
case 5: c=6;
default: c=0;}
value of c?

Question Posted / madhu

Answer Posted / madhu

As t = 3,it goes to case 3.But there is no break in that
case so it proceeds further down to default and c becomes 0.

Is This Answer Correct ?

7 Yes

1 No

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