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void main()
{
int i=5;
printf("%d",i+++++i);
}
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Answer Posted / ashwini
This gives an error. The error is as below:
error C2105: '++' needs l-value
if we correct the code to printf("%d", i++ + ++i);
We get the answer as 12...
The above printf becomes a statement when it sees the
semicolon. Unary operators have right to left associativity.
So, ++i is evaluated first to 6. Then, i++ is evaluated. i++
contributes 6 to addition and then increments i. So, we get
the answer as 12.
| Is This Answer Correct ? | 1 Yes | 1 No |
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