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What is the output of the program given below
#include<stdio.h>
main()
{
char i=0;
for(;i>=0;i++) ;
printf("%d\n",i);
}
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Answer Posted / gajanandon
after for there is semicolon...means empty statement. So no
effect of printf.
so for runs till i (char value) increments in positive
direction and terminates once it exceeds 127 (char
limitation).
Hence finally printf will execute and then prints -128.
| Is This Answer Correct ? | 3 Yes | 0 No |
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