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int main()
{
int i=1;
switch(i)
{
case '1':
printf("hello");
break;
case 1:
printf("Hi");
break;
case 49:
printf("Good Morning");
break;
}
return 0;
}
- 3 Answers
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Answer Posted / vishnu nayak
it will display Hi. In case '1', 1 is a character and it is
converted into ascii equivalent and then tested, which is
not equal to 1.
if the code is like this
swithc(i)
{
case 1:
printf("hi");
break;
case 1:
printf("Hello ");
break;
} then it will surly give compilation error.
| Is This Answer Correct ? | 4 Yes | 2 No |
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