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void main()
{
int a=1;
printf("%d %d %d",a,++a,a++);
}
the output is supposed to be 1 2 2....but it is 3 3 1
this is due to calling conventions of C. if anyone can
explain me how it happens?
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Answer Posted / sumant
In C the parameters are pushed on the stack from right to
left. So
1> it will push a=1 on the stack and do a++ making a=2
2> it will porform ++a making a = 3 and push value 3
3> it will push a on the stack which is 3
so the stack will have values 1 3 3 and it will POP in
the reverse order and thus printf will display 3 3 1
| Is This Answer Correct ? | 52 Yes | 11 No |
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