Answer Posted / vadivelt

3 1 1 2.

To analyse, lets rewrite the prgm.

#include<stdio.h>
#include<conio.h>
main()
{
int a, b, c, d;
a = (1,2,3);
b = 1,2,3;
c = 1,(2,3);
d = (1,2),3;
printf("%d %d %d %d", a, b, c, d);
getch();
}


Note:Precedence of evaluation of the statements would be:
for (1,2,3) it is -> ie., left to right
for 1,2,3 it is <- ie., right to left.

Now,
1. In statement a = (1,2,3); due to the precedence(->)
latest vale of a would be 3.

2. In the same way( <- ) in the statement b = 1,2,3; latest
value of b would be 1.

In statement c = 1,(2,3); and d = (1,2),3; there are two
precedency lavel.

Lets analyse.

3.In c = 1,(2,3); As we know the basic rule in C that the
expression in a statement with braces evaluated first. So
the outcome of (2,3) would be 3(cos., ->), then the
statement c = 1,(2,3); shall be replaced as c = 1, 3; in
runtime. So in the next execution c's latest value would be
1. Cos now precedence would be <-.

4. In the same way, first d = (1,2),3; will be replaced as
d = 2,3 then d holds the value 2 as latest value.

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