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Can we add two byte variables and assign the result to a
byte variable ?
b=b1+b2 where b,b1,b2 are byte types
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Answer Posted / rajesh
Yes,the following is the right way to do so
byte b1=21;byte b2=11;
byte b;
b=(byte)(b1+b2);
| Is This Answer Correct ? | 39 Yes | 5 No |
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