1. Write the function int countchtr(char string[ ], int ch);
which returns the number of times the character ch appears
in the string.
Example, the call countchtr(“She lives in NEWYORK”, ‘e’)
would return 3.
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Answer Posted / vadivel t
#include<stdio.h>
#include<conio.h>
int main()
{
char ptr[100]= "She lives in NEWYORK";
char ch;
printf("ENTER THE CHARACTER:\n");
scanf("%c", &ch);
printf("CHAR %c EXIST %d TIME(S)\n",ch, countchtr(ptr, ch));
getch();
}
int countchtr(char *ptr, char ch)
{
int count = 0;
char ch1;
if(ch >= 97 && ch <= 122)
{
ch1 = ch - 32;
}
else if(ch >= 65 && ch <= 96)
{
ch1 = ch + 32;
}
while(*ptr != '\0')
{ if((*ptr == ch) || (*ptr == ch1))
{
count++;
}
ptr++;
}
return count;
}
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