Answer Posted / vadivel t

Hi Vignesh,

Ur explanation about realloc() is correct. But the answer
is wrong. Because, it is possible to use realloc() before
using malloc() or calloc() function be used.

Lets, try the below code.

int *ptr;
ptr = (int *)realloc(NULL, 5);
printf("%d \n", ptr);

In this code, realloc will allocate five bytes of memory
and will return a valid pointer. It can be used in ur
program.

Conclusion:

It simple means that, if u pass a NULL pointer to a realloc
() function, it will exactly behave as like malloc().

main() { printf("hello"); fork(); }

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