Answer Posted / vadivel t

Hi this code ll work for the second question but first
question i dint understand...

here in souce buff we have 16 nos, in which 1 to 5 repeats
3 times.

but at the end of the program u ll get only nos 1 to 6 as
out in dest buff without duplicate.


Note: Compiler used Visual studio 2005.


#include<stdio.h>
#include<conio.h>
void main()
{
int source[16] = {5,3,4,1,2,1,2,3,4,5,2,3,1,5,4,6};
int dest[6], i, j, count = 0, flag;

int test = 0;
/*Copy the first element*/
dest[0] = source[0];
count++;
for(i = 1; i<= 15; i++)
{
/*Check whether the same element is already
available in the dest buff*/
for(j = 0; j<count; j++)
{
if(dest[j] == source[i])
{
/*Already available*/
flag = 0;
break;

}
else
{
flag = 1;
}
}
if(flag == 1)
{
/*The same element is not available
already - so copy it to the dest buffer*/
dest[count] = source[i];
count++;
}
}

for(i = 0; i<=5; i++)
printf("%d\t",dest[i]);

_getch();
}

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