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how to display 2-D array elements in spiral

Answer Posted / om

#include<iostream>

using namespace std;
//----------------------
void spiral_way(int Row_size,int Column_size,int a[][4])
{
int
i,j,d=0,Current_row_size=Row_size,Current_column_size=Column_size,
Counter=Row_size*Column_size;



while(Counter>0) //Initailly my "Counter" is set to
total no. of elemnet in my 2-D array. so now I will
decrement it as I cover a element.

{

i=d;j=d;

while(j<Current_column_size-1) {
printf("%d\t",a[i][j]); j++; Counter--;}
//this is for printing the first row in forward direction.

while(i<Current_row_size-1) {
printf("%d\t",a[i][j]); i++; Counter--;}
//this is for printing the last cloumn in downward direction.

while(j>d) {
printf("%d\t",a[i][j]); j--; Counter--; }
//this is for printing the last row in backward direction.

while(i>d) {
printf("%d\t",a[i][j]); i--; Counter--; }
//this is for printing the first column in upward direction.

//When I completed the outer rectangle I move in to inner
rectangle by incrementing "d".

//and decrementing the "Current_row_size" and
"Current_column_size".
d++;
Current_row_size--;
Current_column_size--;

}
}

//-------------------------

int main()

{

int a[5][4]={{1,2,3,4},

{5,6,7,8},

{9,10,11,12},

{13,14,15,16},

{17,18,19,20}

};

spiral_way(5,4,a);

//system("pause");

return 0;

}

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