Answer Posted / sandeep

Virtual keyword is used to perform the dynamic binding
instead of early binding. To be brief below is the example

Class base
{
void display()
{
cout<<"in Base";
}
}
Class derived: public base
{
void display()
{
cout<<"in derived";
}
}
void main()
{
base* ptr;

ptr = new derived;
ptr->display();
}

When we execute above program output will be displayed as
"in base", but expected output was "in derived". So compiler
was choosing member function which matches the type of the
pointer rather than the member function which matches the
content of the pointer. But when we use Virtual keyword in
base class, it perform the dynamic binding, i.e., at run
time it choose the function to execute and executes "in
derived". So when we use virtual keyword, compiler will
select the member function which matches the content of the
pointer and it will ignore the member function which matches
the type of the pointer.

What is uint c#?

905

---

Why References are stored on heap and variables on stack?

941

---

Is string passed by reference in c#?

929

---

Explain more on CLR

1157

---

What is difference between assembly and namespace?

929

---

What are the types of methods in c#?

984

---

What does string intern do?

1035

---

1. Describe page life cycle?

2109

---

Which attribute is used in order that the method can be used as webservice?

938

---

Why do we use readonly in c#?

917

---

Is static thread safe?

871

---

Can we customize the serialization process?

958

---

How many bytes is a char c#?

890

---

What are extender provider components? Explain how to use an extender provider in the project.

904

---

What is class in oops with example in c#?

919

---