Answer Posted / sarita

1 KVA system can give you a maximum load putting capacity of
800 watts and if you are putting 100% load on the systems
i.e. 800 watts your maximum output current will be 800/230 =
3.47 A(A.C) and correspondingly for 2 KVA system it will be
2* 3.47= 6.95 A.

For calculating the maximum input current the maximum Load +
battery charging current will be taken into account. i.e.
for 1KVA it will be 3.47 + 2.45 considering the system to be
of 4 batteries and charging current to be 10 A so it will be
5.92 A for 1 KVA system. And it will be 6.95 + 4.904 for the
same charging current with 8 batteries in system so the
total will be 11.85 A.

Regards
Su-kam Executive

What is RSSP in GSM???????

3259

---

Explain the working of a multiplexer.

1032

---

What will happen if we change the polarity of microwave antenna?

2066

---

What is the difference between dcs & plc & scada?

1208

---

please provide me the previous technical papers for ece branch conducted by hpcl

2054

---

needed web address and its directory for objective type question with answer in electronics instrumentation paper.

3197

---

Define what is a rectifier?

1130

---

Explain the difference between latches and flip flop?

931

---

what is the difference between isdn and idn?

8525

---

What is the meaning of tristate signal in electronics?

1022

---

What are the key inputs and factors considered to plan the number of SGSN/GGSN if you have to set up a Greenfield network?

2962

---

sir i want polytechnic lecturers model papers plzzzzzzzzz send me my mail id: manisri.bobbala@gmail.com

2633

---

What is meant by operating point?

994

---

Give some examples of power electronics applications in the day-to-day life?

1051

---

i am btch 4th semester ece student.i want to get idea 6th month indistrial tranning and job in tcs.

2053

---