In the line 12 .jus think new Integer(1) will result 1 and new Integer(2)

Given:
11. public static void main(String[] args) {
12. Integer i = uew Integer(1) + new Integer(2);
13. switch(i) {
14. case 3: System.out.println(”three”); break;
15. default: System.out.println(”other”); break;
16. }
17. }
‘What is the result?
1 three
2 other
3 An exception is thrown at runtime.
4 Compilation fails because of an error on
line 12.

Question Posted / manikandan

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Answer Posted / manikandan

In the line 12 .jus think new Integer(1) will result 1 and
new Integer(2) will result 2 so 1+2=3 which is stored in a i.

so the line 12 can b written as a Integer i=1+3;

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