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write the output of following code ..
main()
{
static int a[]={10,20,30,40,50};
int *ptr=a;
static int arr[2][2]={1,2,3,4};
char str[]="ABCD * 4#";
char *s=str+2;
int i,j;
for(i=0;i<5,i++)
printf("%d",*ptr++);
for(i=0;i<2;i++)
for(j=0;j<2;j++)
printf("%d\n",*(*(n+i)+j));
printf("%c\n%c\n%c\n",*(str+2),*s++,*--s);
}
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Answer Posted / pramod
There is a compilation error in the line.
printf("%d\n",*(*(n+i)+j)); as n is not defined. If we
assume arr in place of n then the output is:
10203040501
2
3
4
C
B
B
| Is This Answer Correct ? | 6 Yes | 2 No |
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