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33. try {
34. // some code here
35. } catch (NullPointerException e1) {
36. System.out.print(”a”);
37. } catch (RuntimeException e2) {
38. System.out.print(”b”);
39. } finally {
40. System.out.print(”c”);
41. }
What is the result if a NullPointerException occurs on line
34?
1 c
2 a
3 ab
4 ac
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Answer Posted / guest
1)
try {
throw new NullPointerException();
} catch (NullPointerException e1) {
System.out.print("a");
} catch (RuntimeException e2) {
System.out.print("b");
} finally {
System.out.print("c");
}
Ans: ac
2) try {
new NullPointerException();
} catch (NullPointerException e1) {
System.out.print("a");
} catch (RuntimeException e2) {
System.out.print("b");
} finally {
System.out.print("c");
}
Ans: c
| Is This Answer Correct ? | 5 Yes | 2 No |
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