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ripple factor of full wave rectifier

Answer Posted / anip upanshu

Vdc = 2Vp/&#960;
Vri = 2Vp/&#960; - Vpsin&#969;t
Vri^2 = 4Vp^2/&#960;^2 - (4Vp^2/&#960;)sin&#952; + Vp^2sin^2&#952;
Vr = &#8730;(1/&#960;)[4&#960;Vp^2/&#960;^2 + (4Vp^2/&#960;)(cos&#960; - cos0) -
(1/2)Vp^2(&#960; - 0 -cos&#960;sin&#960; + cos0sin0)]
Vr = Vp&#8730;(1/&#960;)[4&#960;/&#960;^2 + (4/&#960;)(cos&#960; - cos0) + (&#960;/2)]
Vr = Vp&#8730;[4/&#960;^2 + (4/&#960;^2)(- 1 - 1) + (1/2)]
Vr = Vp&#8730;[1/2 - 4/&#960;^2]
Vr/Vdc = (&#960;/2)&#8730;[1/2 - 4/&#960;^2]
Vr/Vdc = &#8730;(&#960;^2/8 - 1)
Vr/Vdc &#8776; 0.4834258 &#8776; 48.3%

Is This Answer Correct ?    5 Yes 15 No



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