Answer Posted / vignesh1988i

the below program is for getting two numbers as input
(decimal format) and then the below program will convert in
binary and add WITHOUT ANY ARITHMETIC OPERATORS.....



#include<stdio.h>
#include<conio.h>
#define HIGH 1
#define LOW 0
void main()
{
long c[32],i,n,a,b,k,m,A,CARRY=0;
clrscr();
n=31;
printf("enter the value of a&b:");
scanf("%ld%ld",&a,&b);
for(i=0;i<32;i++)
{
k=((a>>i)&1);
m=((b>>i)&1);
if(!(CARRY^HIGH))
{
c[n]=((CARRY^k)^m);
if(!(k^HIGH)||!(m^HIGH))
CARRY=1;
else
CARRY=0;
}
else if(!(k^HIGH) && !(m^HIGH))
{
CARRY=1;
c[n]=k^m;
}
else if(!(k^LOW)||!(m^LOW))
{
if(!(CARRY^HIGH))
{
c[n]=((CARRY^k)^m);
CARRY=0;
}
else
c[n]=k^m;
}
n--;
}
for(i=0;i<32;i++)
printf("%d",c[i]);
getch();
}


thank u

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