int aaa() {printf(“Hi”);}
int bbb(){printf(“hello”);}
iny ccc(){printf(“bye”);}
main()
{
int ( * ptr[3]) ();
ptr[0] = aaa;
ptr[1] = bbb;
ptr[2] =ccc;
ptr[2]();
}
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Answer Posted / susie
Answer :
bye
Explanation:
int (* ptr[3])() says that ptr is an array of pointers to
functions that takes no arguments and returns the type int.
By the assignment ptr[0] = aaa; it means that the first
function pointer in the array is initialized with the
address of the function aaa. Similarly, the other two array
elements also get initialized with the addresses of the
functions bbb and ccc. Since ptr[2] contains the address of
the function ccc, the call to the function ptr[2]() is same
as calling ccc(). So it results in printing "bye".
| Is This Answer Correct ? | 3 Yes | 0 No |
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I need your help, i need a Turbo C code for this problem.. hope u'll help me guys.? Your program will have a 3x3 array. The user will input the sum of each row and each column. Then the user will input 3 values and store them anywhere, or any location or index, temporarily in the array. Your program will supply the remaining six (6) values and determine the exact location of each value in the array. Example: Input: Sum of row 1: 6 Sum of row 2: 15 Sum of row 3: 24 Sum of column 1: 12 Sum of column 2: 15 Sum of column 3: 18 Value 1: 3 Value 2: 5 Value 3: 6 Output: Sum of Row 1 2 3 6 4 5 6 15 7 8 9 24 Sum of Column 12 15 18 Note: Your program will not necessary sort the walues in the array Thanks..
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