main()

{

unsigned char i=0;

for(;i>=0;i++) ;

printf("%d\n",i);

}

Answer Posted / susie

Answer :

infinite loop

Explanation

The difference between the previous question and this
one is that the char is declared to be unsigned. So the i++
can never yield negative value and i>=0 never becomes false
so that it can come out of the for loop.

Is This Answer Correct ?    7 Yes 0 No



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