main()
{
int i=0;
for(;i++;printf("%d",i)) ;
printf("%d",i);
}
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Answer Posted / susie
Answer :
1
Explanation:
before entering into the for loop the checking condition is
"evaluated". Here it evaluates to 0 (false) and comes out of
the loop, and i is incremented (note the semicolon after the
for loop).
| Is This Answer Correct ? | 25 Yes | 9 No |
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