main()
{
char s[ ]="man";
int i;
for(i=0;s[ i ];i++)
printf("\n%c%c%c%c",s[ i ],*(s+i),*(i+s),i[s]);
}
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Answer Posted / susie
Answer :
mmmm
aaaa
nnnn
Explanation:
s[i], *(i+s), *(s+i), i[s] are all different
ways of expressing the same idea. Generally array name is
the base address for that array. Here s is the base address.
i is the index number/displacement from the base address.
So, indirecting it with * is same as s[i]. i[s] may be
surprising. But in the case of C it is same as s[i].
| Is This Answer Correct ? | 37 Yes | 7 No |
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