How to find the given no is odd or even without checking of
any condition and loops. (Hint: Using array)
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Answer Posted / anandi
void main()
{
int n;
char s[20][20]={"even","odd"};
printf("Enter the no.:");
scanf("%d",&n);
n=n%2;
printf("th no. is %s",s[n]);
getch();
}
| Is This Answer Correct ? | 3 Yes | 3 No |
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