Write out a function that prints out all the permutations of
a string.
For example, abc would give you abc, acb, bac, bca, cab,
cba. You can assume that all the characters will be unique.
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Answer Posted / patrick
//I think it can be implemented this way rather
simply..check it..
main(){
char a[15];
int len,fiblen,i,j,count=0,div,on,to;
printf("enter the string\n");
scanf("%s",a);
fiblen=fib(strlen(a));
div=fiblen/(strlen(a));
for(i=0;i<strlen(a);i++){
for(j=0;j<(strlen(a)-1);j++){
for(on=1;on<(strlen(a)-1);on++){
to=on+1;
swap(&a[on],&a[to]);
count++;//no: of anagram
printf("(%d) %s\n",count,a);
}
}
swap(&a[0],&a[i+1]);
}
}
swap(char *a,char *b){
char temp=*a;
*a=*b;
*b=temp;
}
int fib(int a){
if(a==1)
return(1);
else
return(a*fib(a-1));
}
| Is This Answer Correct ? | 4 Yes | 2 No |
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