Answer Posted / pushpa

int num[3];
int i,j,p=0,count_1=0,count=0,n;

n= 3;
for(i=0;i<n;i++)
{
scanf("%d",&num[i]);
}


for(i=0;i<n;i++)
{
for(j=0;j<n;j++)
{
if(num[i] == num[j])
count_1=0;
else
count++;
}
if(count == n-1)
{
printf("The number which occurs once is %d\n",num[i]);
}
count = 0;

}

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