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what is the output of following question?
void main()
{
int i=0,a[3];
a[i]=i++;
printf("%d",a[i]
}
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Answer Posted / vignesh1988i
my opinion or wat i think is that ,
a[i]=i++; is given so...
here i++ is a post increment operation , so first it will assign the value to a[0]=0 , so a[0] will have 0 , and in next line a[i] is given in printf , so the value a[1] should get printed that will be garbage value.......
thank u
| Is This Answer Correct ? | 4 Yes | 1 No |
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