Answer Posted / vignesh1988i

here using pointers we can easily do the above..........


#include<stdio.h>
#include<conio.h>
#include<alloc.h>
void main()
{
char a[50],*ptr,*pointer;
int n,i,j,k;
printf("enter the string:");
gets(a);
for(i=0;a[i]!='\0';i++)
n++;
pointer=(char*)malloc((n+1)sizeof('2'));
j=0;
for(i=0;a[i]!='\0';)
{
if(a[i]==' ')
{
*(pointer+(n-j-1))=a[i];
i++; j++;
}
else
{
ptr=&a[i];
for(k=0;a[i+1]!=' '&&a[i+1]!='\0';k++)
i++;
for(k=0;k<((&a[i]-ptr)+1);k++)
{
*(pointer+(n-j-1))=*(ptr+(&a[i]-ptr)-k);
j++;
}
}
i++;
}
*(pointer+(n+1))='\0';
for(i=0;i<n;i++)
printf("%c",*(pointer+i));
getch();
}



thank u

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