How do you read arguments in a shell program - $1, $2 ..?
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Answer Posted / madhavi
to read command line argments we hav to use echo $1
$2........whre $0-gives name of program,$#-gives number of
arguments passed and $* gives all the arguments.
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Hello all, This is my assignment on shell scripting, can anyone help me regarding this ? Create a shell script which connects to the database In second shell script include the first script for the DB connection Create a table (PRADEEP_DATA) with 2 columns (name, value) In Third shell script include the first script for the DB connection And insert/delete the values from the Table, by accepting input from the user This functionality should be a menu driven Program: 1) Insert to the database a. Name b. value 2)Delete from the database a.Name b.value Exception handling needs to be taken care.
