This boils down to (10 +10 * 10 + 10) so answer is 120 ... but if the sa

#define d 10+10
main()
{
printf("%d",d*d);
}

Question Posted / vrushali

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Answer Posted / vrushali

This boils down to (10 +10 * 10 + 10)

so answer is 120 ... but if the same macro was rewritten as
#define d (10 + 10)

then d * d = (10 + 10 ) * (10 + 10)
= 20 * 20
= 400....

Pure macro concept....

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