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1)
int i=5;
j=i++ + i++ + i++;
printf("%d",j);This code gives the answer 15.But if we
replace the value of the j then anser is different?why?

2)int i=5;
printf("%d",i++ + i++ + i++);
this givs 18.

Question Posted / prasoon

Answer Posted / prasoon

both the codes possess undefined behaviour because the value
of i is changing more than once between two sequence points...

hence my answer is undefined behaviour

Is This Answer Correct ?    14 Yes 6 No



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