#define min((a),(b)) ((a)<(b))?(a):(b)
main()
{
int i=0,a[20],*ptr;
ptr=a;
while(min(ptr++,&a[9])<&a[8]) i=i+1;
printf("i=%d\n",i);}
Answer Posted / bj
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any function have arguments one or more OR not . it is compulsary a) any function compulsary have one or more arguments b) any function did not have arguments. It is not compulsary c) it is optional it is not compulsary d) none of the above
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You have given 2 array. You need to find whether they will
create the same BST or not.
For example:
Array1:10 5 20 15 30
Array2:10 20 15 30 5
Result: True
Array1:10 5 20 15 30
Array2:10 15 20 30 5
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One Approach is Pretty Clear by creating BST O(nlogn) then
checking two tree for identical O(N) overall O(nlogn) ..we
need there exist O(N) Time & O(1) Space also without extra
space .Algorithm ??
DevoCoder
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Posted 3 months ago #
#define true 1
#define false 0
int check(int a1[],int a2[],int n1,int n2)
{
int i;
//n1 size of array a1[] and n2 size of a2[]
if(n1!=n2) return false;
//n1 and n2 must be same
for(i=0;i
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