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1)
int i=5;
j=i++ + i++ + i++;
printf("%d",j);This code gives the answer 15.But if we
replace the value of the j then anser is different?why?
2)int i=5;
printf("%d",i++ + i++ + i++);
this givs 18.
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Answer Posted / amey
in the 1st case post increment will be done at the end of
the statement that is 15 is assigned to 'j' then 'i' will
increment 3 times bcoz 3 post increments r there.
in the later case first 15 assign to 'i' then increment
3 times and assign to 'i'
| Is This Answer Correct ? | 5 Yes | 4 No |
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