here a and b are local variable in function swap() where a and b are swap

void swap(int a,int b)
{
a=a+b;
b=a-b;
a=a-b;
}

in this code always gives the same result for all case

Question Posted / moorthy

Answer Posted / moorthy

here a and b are local variable in function swap() where a
and b are swapped inside swap().so that swaping does not
affect variable in main().

Is This Answer Correct ?

12 Yes

1 No

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