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main()
{
char *p1="Name";
char *p2;
p2=(char *)malloc(20);
while(*p2++=*p1++);
printf("%s\n",p2);
}
what is the output?
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Answer Posted / ali fakoor
A part of uninitialized (and/or unowned) memory after (and
including) the sixth byte of the malloc-ed memory will be
printed out until reaching a NULL character in the memory
somewhere!
| Is This Answer Correct ? | 6 Yes | 4 No |
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