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what is the output of the following program?
#include<stdio.h>
void main()
{
float x=1.1;
while(x==1.1)
{
printf("\n%f",x);
x=x-0.1;
}
}
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Answer Posted / vignesh1988i
for the first time the loop will be true and it will print as 1.100000 , after reading the next line x will be 1.0, so again when it comes into while loop 1.000000 not equal to 1.100000 so it will come outside the loop
| Is This Answer Correct ? | 4 Yes | 20 No |
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