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You are given any character string. Find the number of sets
of vowels that come in the order of aeiou in the given
string. For eg., let the given string be DIPLOMATIC. The
answer returned must be "The number of sets is 2" and "The
sets are "IO and AI". Vowels that form a singleton set must
be neglected. Try to post the program executable in gcc or
g++ or in java.
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Answer Posted / vadivel_152
#include<stdio.h>
#include<string.h>
int vowelsubset();
void separate();
char vowel[] = {'a','e','i','o','u'};
char str[100],res[50];
int main()
{
scanf("%s",str);
separate();
printf("The No. of sets are: %d\n",vowelsubset());
return 0;
}
void separate()
{
int i,j,x=0;
for(i = 0;i<strlen(str);i++)
for(j = 0;j<5;j++)
if(str[i] == vowel[j])
res[x++] = str[i];
res[x] = ''\0;
}
int vowelsubset()
{
if( (strlen(res)==0 )|| (strlen(res)==1) )
return 0;
int cnt = 0,i,j,x,k,flag;
for(i = 0;i<strlen(res);i++)
{
for(j = 0;j<5;j++)
if( (res[i] == vowel[j]) && (vowel[j]!='u'))
{
flag = 0;
for(k = i+1;k<strlen(res);k++)
{
if(res[k]<=vowel[j])
{
i = k-1;
goto label;
}
for(x = j+1;x<5;x++)
if(res[k] == vowel[x])
flag = 1;
}
label:
if(flag == 1)
cnt++;
}
}
return cnt;
}
| Is This Answer Correct ? | 4 Yes | 1 No |
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