Answer Posted / anshul kumar goyal
According to KCL
Cuurent coming to the point+current going away from the
point=0
Therotically same rule applies in star connection only if
load is balanced, but practically current at neutral point
is not 0 as .
To make the neutral current 0, earthing is provided in the
transformer commissioned at DT through a bush.
This earthing provides minimum resistance path for the
accessive current.
| Is This Answer Correct ? | 9 Yes | 7 No |
Post New Answer View All Answers
What is the best thing to protect the motor from running over full current. CT or O/L or pressure transducer at the given pressure rating
what is control supply rating of a machine
what is the difference between 2 way and 4 pole selector switch???
please send me previose rrb junior engineer qustion papers
Why wind turbines wheels rotate constantly
What is the Minimum winding resistance of motors ( small & big)? referance range
What is the ideal position cooling fan inside the dc motor?
What are :- AC Distribution Board (Single & Double Front) DC Distribution Boards Distribution Board LT Breaker Panel.
what are safety measures in /control in diesal engine/ explain them?
What are the raitings of Mcb,mccb and Acb in detail ??
What are the Formula of computing Back up Time of 500kVA UPS with 4 Battery Banks, each bank composed of 43 pcs of Batteries 12V150Ah. How to compute the Back up Time of UPS? We have also 3X500kVA UPS running in Parallel same composition as I write above.
i have a 1500kVA transformer what is the kWH meter i need to use?
We have drive feeding an output contactor for a 5000 hp motor @ 5kV application. The motor FLA is 629amps x 1.25% service factor = 786.25 amps The cable that we current have in place between the drive and the output contactor is 350kcmil- MV-105 (parallel cables). Per the NEC table 310.60 (C) (69). This show the cable ampacity is at 615 amps per cable for a rating of 1230 amps. We have derated the cable for the cable tray and the multiple cables application and our calculations show that after the correction factor factor we are at 922amps. 1230 amps x .75% correction factor factor = 922.5 amps. The customer is driving us to then use another safety factor of .25% off of the already derated cable. Can you please provide a longhand calculation for your solution on this application?
Mention the disadvantages of low power factor? How can it be improved?
How it can worked plc based electrical system And which type of software using.