Answer Posted / madhu

We can't give both super() and this()in a constructor,
because both of these statements must be the first
statements in constructor. if you give super() as the first
statement then compiler error will come with this() call.
and vice versa.
but you can call the members with both super and this in a
constructor. here is the code.
class Base
{
Base()
{
System.out.println("Base constructor");
}
void m1()
{
System.out.println("m1 of Base");
}
}
class Derived extends Base
{
Derived()
{
super();//it is ok.
this();//raises compiler error
//but we can call the members with super and this
super().m1();//make sure that super()in
line must be marked comment
this().m1();
System.out.println("Derived constructor");
}
void m1()
{
System.out.println("m1 of Derived");
}
public static void main(String[] args)
{
Derived d=new Derived();
}
}
it works out

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