2. Counting in Lojban, an artificial language developed
over the last fourty years, is easier than in most languages
The numbers from zero to nine are:
0 no
1 pa
2 re
3 ci
4 vo
5 mk
6 xa
7 ze
8 bi
9 so
Larger numbers are created by gluing the digit togather.
For Examle 123 is pareci
Write a program that reads in a lojban string(representing
a no less than or equal to 1,000,000) and output it in
numbers.
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Answer Posted / abdur rab
#include <stdio.h>
int decimal_from_logban ( char* cp_logban )
{
if ( !strcmp ( cp_logban, "no" ) ) return 0;
if ( !strcmp ( cp_logban, "pa" ) ) return 1;
if ( !strcmp ( cp_logban, "re" ) ) return 2;
if ( !strcmp ( cp_logban, "ci" ) ) return 3;
if ( !strcmp ( cp_logban, "vo" ) ) return 4;
if ( !strcmp ( cp_logban, "mk" ) ) return 5;
if ( !strcmp ( cp_logban, "xa" ) ) return 6;
if ( !strcmp ( cp_logban, "ze" ) ) return 7;
if ( !strcmp ( cp_logban, "bi" ) ) return 8;
if ( !strcmp ( cp_logban, "so" ) ) return 9;
}
void logban_2_decimal ( char* _lojban, int* _decimal )
{
char lojban_array [3];
memset ( lojban_array, '\0', 3 );
if ( ( NULL != _lojban ) && ( '\0' != *( _lojban +
2 ) ) ) {
logban_2_decimal ( _lojban + 2, _decimal +
1 );
strncpy ( lojban_array, _lojban, 2 );
*_decimal = decimal_from_logban (
lojban_array );
} else {
strncpy ( lojban_array, _lojban, 2 );
*_decimal = decimal_from_logban (
lojban_array );
}
}
int main ( int argc, char* argv [] )
{
char number_lojban [] = {"sopareci"};
int number_decimal [8];
int i = 0;
logban_2_decimal ( number_lojban, number_decimal ) ;
printf ( "\nLojban :%s", number_lojban );
printf ( "\nDecimal :" );
for ( i = 0; i < ( strlen ( number_lojban ) / 2 );
i++ )
printf ("%d", number_decimal [ i ] );
return ( 0 );
}
| Is This Answer Correct ? | 2 Yes | 2 No |
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