Answer Posted / zafar

No, you cannot create an instance of an interface. An
interface has no implementation - a class that implements
the interface specifies the implementation.

However, you can ofcourse have a reference variable of an
interface type that points to an instance of a class that
implements the interface. For example:

// List is an interface, ArrayList implements interface List
List data = new ArrayList();


It's good practice to program like this - program to an
interface, not an implementation. If you want to know more
about that design principle, see, for example:
[url=http://www.artima.com/lejava/articles/designprinciples.
html]Design Principles from Design Patterns[/url]

What is the difference between numeric and integer?

957

---

What is identifier in java?

1038

---

What is JDBC Driver interface?How can you retrieve data from the ResultSet

2054

---

How listener identify that the event came from a particular object?

1957

---

What is a bubble sort in java?

908

---

How are multiple inheritances done in Java?

1100

---

What is a numeric literal?

1011

---

Explain the scope of a variable.

1034

---

What is difference between local variable and global variable?

958

---

What is difference between checked and unchecked exception in java?

967

---

Does java vector allow null?

903

---

What is data member in java?

969

---

What are the various access specifiers in java?

961

---

How does thread synchronization occurs inside a monitor?

1056

---

Can a class extend more than one class?

1063

---