public class AboutStrings{
public static void main(String args[]){
String s1="hello";
String s2="hel";
String s3="lo";
String s4=s2+s3;
//to know the hash codes of s1,s4.
System.out.println(s1.hashCode());
System.out.println(s4.hashCode());
// these two s1 and s4 are having same hashcodes.
if(s1==s4){
System.out.println("s1 and s4 are same.");
}else
System.out.println("s1 and s4 are not same.");
}
}
Somebody told me that, == operator compares references of
the objects.
In the above example even though s1 and s4 are refering to
same object(having same hash codes),
it is printing s1 and s4 are not same.
Can anybody explain in detail why it is behaving like this?
Thanks in Advance
RavuriVinod
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Answer Posted / vishal arora
it is true that == compares the refernce but in this case
it is retuning the false because the refernce is not the
same.
Strings are final in Java
so s4=s2+s3 will create a new String and s1 and s4 will
refer to two differnt strings
also hashcode will be equal for the same refernce but it
may also be equal for differnt refernces hascode is nothing
but a bucket so there can be multiple object refernce in
same bucket the only condition is for equals method
returning true must have same hashcode
so always use .equals methods and not == to compare the
strings
| Is This Answer Correct ? | 10 Yes | 0 No |
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