KUP-04077: unknown format specifier in file name string



KUP-04077: unknown format specifier in file name string..

Answer / guest

Cause: A format specifier is a percent sign followed by a
character. The percent sign and character are replaced by a
value depending on the character. This error occurs when the
character following the percent sign is not defined to have
a value.

Action: See the documentation for information on valid
format specifiers. If the file to be opened needs to have a
percent sign in its name then use two pecent signs. They
will get replaces by a single percent sign in the resulting
file name.

Please add more information about this Error

Is This Answer Correct ?    0 Yes 0 No

Post New Answer

More Oracle Errors Interview Questions

NNC-00500: warning: "string" parameter value is illegal, setting to string

1 Answers  


ORA-28518: data dictionary translation has illegal translation type

1 Answers  


ORA-01563: rollback segment is PUBLIC, need to use the keyword PUBLIC

1 Answers  


ORA-06034: NETDNT: connect failed, partner exited unexpectedly

1 Answers  


ORA-06438: ssaio: the asynchronous read was unable to read from the database file.

1 Answers  






ORA-31515: CDC change source string already exists

1 Answers  


ORA-02880: smpini: Could not register PGA for protection

1 Answers  


RMAN-08018: channel string: starting archive log restore to user-specified destination

1 Answers  


ORA-01508: cannot create database; error in file 'string' at line string

1 Answers   Lionbridge,


LRM-00108: invalid positional parameter value 'string'

1 Answers  


RMAN-06529: CHANGE ... KEEP not supported for ARCHIVELOG

1 Answers  


ORA-07253: spdes: semctl error, unable to destroy semaphore set.

1 Answers  


Categories